39f^2+2f=0

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Solution for 39f^2+2f=0 equation:



39f^2+2f=0
a = 39; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·39·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*39}=\frac{-4}{78} =-2/39 $
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*39}=\frac{0}{78} =0 $

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